How many oxygen atoms are present in 111 g of quick lime?
1) 11.93 * 10^23
2) 9.31 * 10^24
3) 111.9 * 10^21
4) 1.15 * 10^25
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➡️ATOMIC MASS OF Ca=40 u
➡️ATOMIC MASS OF O=16 u
⏩TOTAL ATOMIC MASS =40+16=56
1 MOLE =111/56
1.98
TOTAL MASS=6.022*10 to the power 23*1.98
119239.56*10 to the power 23
THE CORRECT ANSWER IS
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OPTION A.
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