how many oxygen atoms are present in 16g of ozone (O3)?
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Molecular mass of O3 is 16×3=48 . That means one mole of O3 will contain 48 grams.
Hence, 16 g of O3 will be equal to 1/3 moles.
Now acc to avogadro's Number “1 mole of any element is equal to 6 ×10°23 atoms”
So 1/3 moles of O3 will have 2×10°23 atoms
Hence, 16 g of O3 will be equal to 1/3 moles.
Now acc to avogadro's Number “1 mole of any element is equal to 6 ×10°23 atoms”
So 1/3 moles of O3 will have 2×10°23 atoms
ariyan187:
ku
but how do u know mole concept
aaaaaa......
i think it is the syllabus of 10th
aaase heee.....
oh
mera muh juukh gaya
11th class ka que h
10 th me bhi h
kyu??
Answered by
1
Given - Mass of ozone
Find - Number of oxygen atoms
Solution - 1 mole of any molecule contains Avogadro's number of atoms.
Number of moles = mass/molar mass
Molar mass of ozone = 48 gram/mol.
Number of moles = 16/48
Performing division
Number of moles = 0.3
Number of atoms = 0.3*6.02*10²³
Performing multiplication
Number of atoms = 2*10²³
Hence, the number of oxygen atoms are 2*10²³.
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