Question

How many oxygen atoms are present in 2.28 moles of nitric acid

Answer 1

Answer:

4.12x10^24

Explanation:

nitric acid is HNO3

so one mole of it contains 3 mole oxygen atoms...

2.28 mole of it contains 3x2.28 moles of oxygen atoms..

thats is 6.84 moles of oxygen atoms...

1 mole refers to 6.022x10^23 atoms..

total atoms are 6.84x6.022x10^23 and it comes out to be

41.19x10^23 or 4.119x10^24

Answer 2

There are 4.12$\times 10^{24}$ atoms of oxygen.

Explanation:

One nitric acid molecule is represented as HNO$_3$

1 molecule of nitric acid contains one atom of hydrogen, one atom of nitrogen, and three atoms of oxygen.

One mole of any substance contains $6.023\times 10^{23}$ particles

So, in 1 mole of nitric acid, there are 3 times $6.023\times 10^{23}$ oxygen atoms

This implies in 2.28 moles of nitric acid there would be 2.28$\times 3\times 6.023\times10^{23}$atoms of oxygen.

So, the number of atoms of oxygen = 41.19$\times 10^{23}$ atoms = 4.12$\times 10^{24}$ atoms