Question

HOW MANY OXYGEN ATOMS ARE PRESENT IN 22G OF CO2.??? WITH SOLUTION PLSSSS .... ☺☺☺☺

Answer 1

Given

Co2

So in this we have 1 mole of carbon and 2 moles of oxygen

Mass of one mole of carbon = 12

Mass of one mole of oxygen =16

Total mass =12+(16x2)

=12+32

=44g

1 mole of Co2 having 44g mass

Now we are having 22g

So

Dividing it with 2

Then we get half mole of carbon and 1 mole of oxygen

22g=1/2 mole of carbon + 1 mole of oxygen

1 mole of oxygen contains 6.023 x10²³ atoms of oxygen.

Therefore 22g of Co2 contains 6.023x10²³ atoms of oxygen

This is ur ans hope it will help you in case of any doubt comment below

Answer 2

✨Heya!!!!✌

✍Your answer⬇⬇⬇⬇

Molecular wt. of CO2= 12+16+16= 44

Then, in 44g of CO2 there are 6.02×10^23 molecules

A/q,
Since, In 44g CO2 there are 6.02×10^23 molecules

So, In 22g CO2 there are 3.01×10^23 molecules

Now, since each molecules of CO2 contain 2 oxygen atoms

So, 22g CO2 contain oxygen atom= 6.023×10^23×1/2×2=6.023×10^23

Hope it helps☑

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