how many oxygen atoms are present in 50g of CaCO3
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∴ 50g of CaCO3=1. 5∗(6. 022∗1023)=9. 035∗1023 oxygen atoms.
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Answer:
Molecular mass of CaCO3= 40+12+3×16 = 100 No. mole of CaCO3 = 50g/100g = 0.5 0.5 mole of CaCO3 contains 1.5
moles of oxygen atoms
No. of oxygen atoms = 1.5 × 6.022×1023 = 9.033×1023 atoms
Mass of Oxygen atoms = 1.5 × 16 = 24 g.
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