Question

how many oxygen atoms are present in 88 g of CO2 ?

Answer 1

atomic mass of CO2 is
$12 + 16(2) = 12 + 32 = 44g$
so no of moles of CO2 in 88g co2 is
$\frac{given \: mass}{molar \: mass} = \frac{88}{44 } = 2$
hence two molecules of Co2 are present in 88 g and in 1 molecule there are 2 oxygen atom so in 2 co2 molecule
no of oxygen atom are
$2x2 = 4atom$

Answer 2

Your answer will be 4