Question

how many oxygen atoms are present in 88g of carbon dioxide
with explanation​

Answer 1

Answer:

number of atom=1.2044×10^24

Explanation:

number of mole=88÷44=2mol

number of atom =2mol×6.022×10^23=12.044×10^23=1.2044×10^24

Answer 2

Answer:

hey mate here is your answer:

Explanation:

As one molecule of CO contains 1 atom of oxygen, therefore there are 6.023 X 1023 atoms of oxygen present in 6.023 X 1023 molecules of CO.

molar mass of CO2= 12 + 16 x 2 = 44g

44g of CO2 gives 1 mol of CO2

88g of CO2 gives 2 mol of CO2

1 mol of CO2 has 2 mol of O2

2 mol of Co2 has 4 mol of O2

So,

number of atoms = no. of moles x Avogadro's number = 4 x 6.023 x 10²³

hope it will help you...