Question

How many oxygen atoms are present in a tablet weighing 360 mg of aspirin

Answer 1

Answer:

0.04816×10^23

FORMULA OF ASPIRIN

C9H8O4

NO OF O ATOMS IN 1 ASPIRIN MOLECULE

IS 4 ATOMS

MOLAR MASS OF ASPIRIN IS

180g/mol

n of moles of aspirin

= mass/molar mass

=0.360/180

=0.002mol aspirin

in 1 molecule of aspirin there is 4 oxygen atoms

so in 0.002 mol of aspirin molecule

( 1mol=6.02×10^23 entities)

so 0.002 mol of ASPIRIN =0.002×6.02×10^23

=0.01204×10^23molecules

so there is 0.01204×10^23 molecules in 2 mol

of ASPIRIN

so in 0.01204×10^23 molecules we have

=0.01204×10^23×'4'

0.04816×10^23 oxygen atoms is present in 360 mg