Question

how many oxygen atoms are there Ba3(PO4)2 in 6.025g (Ba=137,P=31)​

Answer 1

Answer:

here's your answer

Explanation:

Ba3(PO4)2 is Barium phosphate

Answer 2

The number of oxygen atoms in bariumphosphate is $4.82\text{ }\times \text{ }{{10}^{22}}$.

Explanation:

• Given mass of bariumphosphate is $6.025g$.
• The atoms present in barium phosphate are barium,phosphorous and oxygen.
• Molar mass of bariumphosphate is $602.5g$.
• Number of moles of a substance is the ratio of given mass to molar mass.
• Therefore number of moles of barium phosphate $=\[\frac{6.025}{602.5}=\frac{1}{100}={{10}^{-2}}\]$
• One molecule of bariumphosphate contains eight oxygen atoms.
• One mole of any substance have avogadro number of molecules in it.
• Therefore ${{10}^{-2}}$  moles of bariumphosphate has $\[8\times {{10}^{-2}}\times ~6.023\text{ }\times \text{ }{{10}^{23}}=4.82\text{ }\times \text{ }{{10}^{22}}~\]$ atoms.