Question

How many oxygen atoms will be present in 88 gram of seo2?

Answer 1

Molar mass of CO2 = 44g/mol

Number of moles of CO2 present in 88g of CO2 = 88g/44g mol-1

= 2 moles

1 mole of CO2 contains 2 moles of Oxygen atoms. Hence 2 moles of CO2 contains 4 moles of Oxygen atoms

1 mole of oxygen contains 6.023 X 1023 atoms of oxygen

4 moles of oxygen contains = 4 X 6.023 X 1023

= 24.092 X 1023

= 2.4092 X 1024 atoms of oxygen

Therefore 88g of CO2 Contains 2.4092 X 1024 atoms of oxygen

Answer 2

12.02multiply 1023is the anzwer