Question

How many oxygen atoms will be present in 88g of CO2?​

Answer 1

Answer:

Since 1 mole co2 has 2 moles of O atom 2 moles ie 88 gm will have 4 moles which is 4 times avogardos no of atom ie 4* 6.023 *10^23.

Answer 2

Step-by-step explanation:

First calculate moles CO2. Then calculate moles O. Then multiply mol O by 6.022×10^23 atoms/mol to calculate atoms of O.

Calculate moles CO2 using the formula:

n = m/M, where:

n = mole

m = mass = 88 g CO2

M = molar mass CO2 = 44.009 g/mol

n CO2 = 88 g CO2/44.009 g/mol = 2.0 mol CO2

The chemical formula CO2 tells us that one mole of the compound contains two moles of oxygen.

Calculate mol O by multiplying 2 mol CO2 by the mole ratio of mol O to mol CO2

2 mol CO2 × 2 mol O/1 mol CO2 = 4 mol O

Calculate number of atoms of O by multiplying mol O by 6.022×10^23 atoms/mol.

4 mol O × (6.022×10^23 atoms/mol) = 2.4×10^24 atoms O