how many oxygen molecules are needed to synthesize 0.245g of carbon monoxide by controlled reaction with carbon
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O2 (g) + 2C (s) = 2CO (g)
1 mole of oxygen reacts with 2 moles of carbon to produce 2 moles of CO.
Now 0.245g of CO = 0.245/28 = 0.0088 mole and this will require 0.0088/2 = 0.0044 mole of oxygen.
Every mole of oxygen contains 6.022 x 10^23 molecules of oxygen. Hence 0.0044 mole will contain 6.022 x 10^23 x 0.0044 = 2.65 x 10^21 molecules of oxygen.
1 mole of oxygen reacts with 2 moles of carbon to produce 2 moles of CO.
Now 0.245g of CO = 0.245/28 = 0.0088 mole and this will require 0.0088/2 = 0.0044 mole of oxygen.
Every mole of oxygen contains 6.022 x 10^23 molecules of oxygen. Hence 0.0044 mole will contain 6.022 x 10^23 x 0.0044 = 2.65 x 10^21 molecules of oxygen.
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