Math, asked by puj2412, 5 months ago

How many pair of integers (A,B) exist such that the product of A.B and HCF (A;B) 1080​

Answers

Answered by dsk75
0

Step-by-step explanation:

A×B = 1080

HCF(A,B) = 1080

=> LCM(A,B) = [A×B]/[HCF(A,B)] = 1080/1080 = 1

=> LCM (A,B) = 1

but LCM of any 2 integers can't be 1

SO, NO TO INTEGERS EXIST SUCH THAT THE PRODUCT OF A.B AND HCF (A,B) IS 1080

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