How many pair of integers (A,B) exist such that the product of A.B and HCF (A;B) 1080
Answers
Answered by
0
Step-by-step explanation:
A×B = 1080
HCF(A,B) = 1080
=> LCM(A,B) = [A×B]/[HCF(A,B)] = 1080/1080 = 1
=> LCM (A,B) = 1
but LCM of any 2 integers can't be 1
SO, NO TO INTEGERS EXIST SUCH THAT THE PRODUCT OF A.B AND HCF (A,B) IS 1080
Similar questions
Math,
2 months ago
English,
2 months ago
Math,
2 months ago
Math,
5 months ago
Social Sciences,
5 months ago
CBSE BOARD X,
10 months ago
Math,
10 months ago