Question

How many pairs (A, B) are possible in the number 479865AB if the number is divisible by 9 and it is given that the last digit of the number is odd?

A) 5 B) 6 C) 9 D) 11

Answer 1

Answer:

(B) 11 is a correct answer

Answer 2

Answer:

the correct answer is A) 5

if a number is divisible my 9 then the addition of all the digits should also be divisible by 9.

4+7+9+8+6+5+a+b = 39+a+b

multiples of 9 are 9 18 27 36 45 54

maximum values of a and b is 9

9+9=18 so 39+18= 57 so take less than 57 multiples

so A+B = 6 ,since 39+a+b should be equal to 45

and A+B = 15 TO BE A MULTIPLE OF 9

SO the pairs are

3+3 5+1 1+5 6+9 8+7.