How many pairs (m n) of integers satisfy the equation 4^m=n^2+15?
Answers
Answered by
15
substitute values of m and n
m = 2 and n=1
satisfies this equation and since n^2 value of n=-1 also considered
another one is m=3 and n=7
so, pairs is (2,1) , (2,-1), (3,7), (3,-7)
totally 4 pairs.
Similar questions