Math, asked by HarshAgrawal007, 1 year ago

How many pairs of letters are there in the word recreation which have number of letters between them in the word One Less than number of letters between them in the English alphabet ?
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Answers

Answered by luvkushhero
2

Answer:


Step-by-step explanation:

Three


renukaa: Explain
Answered by Anonymous
6

Answer:

4 pairs.

Step-by-step explanation:

The word is - RECREATION

As per the question,

(number of letters between any two letter in the word) + 1 = (number of letters between the same 2 letters in English alphabet)

Here I'm denoting the 2nd letter E as E₁ and the 5th letter E as E₂.

Now lets start with the first letter R(18th letter in alphabet); There is no such match.

Next letter E₁(5th letter in the alphabet); Now see there is the third letter C , between E & C there is no letter in the word but in the English alphabet a letter D is present in between  C & E (C, D, E).

Thus no. of letters inbetween E & C in the word = 0

no. of letters inbetween E & C in English alphabet = 1  

0 + 1 = 1

So, 'E₁ & C' is a pair(1st pair).

Now, for the same letter, 2nd letter E₁; between E & N there are 7 letters(E C R E A T I O N) in the word and in English alphabet there are 8 letters between E and N(14th letter in alphabet) (E, F, G, H, I, J, K, L, M, N).  

Thus no. of letters inbetween E & N in the word = 7

no. of letters inbetween E & C in English alphabet = 8  

7 + 1 = 8

So, 'E₁ & N' is a pair(2nd pair).

Now, for 3rd letter C; between C & I there are 4 letters(C R E A T I) in the word and in English alphabet there are 5 letters between C and I(9th letter in alphabet) (C, D, E, F, G, H, I).

Thus no. of letters inbetween C & I in the word = 4

no. of letters inbetween C & I in English alphabet = 5  

4 + 1 = 5

So, 'C & I' is a pair(3rd pair).

Now, for 5th letter E₂; between E₂ & I there are 2 letters(E A T I) in the word and in English alphabet there are 3 letters between E₂ and I(9th letter in alphabet) (E, F, G, H, I).

Thus no. of letters inbetween C & I in the word = 2

no. of letters inbetween C & I in English alphabet = 3  

2 + 1 = 3

So, 'E₂ & I' is a pair(4th pair).

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