Question

how many pairs of natural nos. have their square difference 45?​

Answer 1

Answer:

3

Step-by-step explanation:

(x2-y2)=45;

Or, (x-y)(x+y)=45.

Thus, the factors of 45 possibles are 15, 3, 9, 5, 1 and 45.

Hence, numbers are 9 and 6 or 7 and 2 or 23 and 22.

So, number of such pairs = 3.

Answer 2

Answer:

(x2-y2)=45; Or, (x-y)(x+y)=45. Thus, the factors of 45 possibles are 15, 3, 9, 5, 1 and 45. Hence, numbers are 9 and 6 or 7 and 2 or 23 and 22.