Question

How many pairs of the alternate numbers are there in the
given sequence that have a difference of 3 among
themselves?
13679245678524781356865​

Answer 1

Answer:

more than 4

Step-by-step explanation:

13679245678524781356865​

first diff = 6 - 9

second diff = 2 - 5

third diff = 3 - 6

fourth diff = 5 - 8

fifth diff  = 8 - 5

Whether the difference is negative or positive, the difference is 3 among themselves.

Answer 2

5

Step-by-step explanation:

1 3 6 7 9 2 4 5 6 7 8 5 2 4 7 8 1 3 5 6 8 6 5

As we can see the series given below, we have to find alternate numbers which have difference of 3. Lets see such pairs one by one.

1. 3rd number and 5th number i.e 6 and 9 (9-6=3)

2. 6th number and 8th number i.e 2 and 5 (5-2=3)

3. 18th number and 20th number i.e 3 and 6 (6-3=3)

4. 19th number and 21th number i.e 5 and 8 (8-5=3)

5. 21th number and 23rd number i.e 8 and 5 (8-5=3)

Therefore, there are total 5 such alternate pairs which has difference of 3 between them.