Question

how many particle will be present in 270 gram of glucose calculate the mole also

Answer 1

glucose = C6H12O6 = 72 +12 + 96 = 180

moles = wt/mol.wt = 270/180 = 1.5 moles.

1 mole contains 6.023 x 10^23 glucose molecules.

therefore 1.5 moles contains 9.0345x10^23 molecules of glucose.

Answer 2

Answer:

The correct answer to this question is 1.5 moles.

Explanation:

Given - 270 grams of glucose.

To Find - How many-particle will be present in 270 grams of glucose calculate the mole.

A mole is a unit of measurement for the amount of a substance that has the same number of particles as 12.000 grams of carbon-12.

Glucose =  $C_{6}H_{12}O_{6}$   = 72 + 12 + 96 = 180

The moles = wt / mol.wt = 270/180 = 1.5 moles.

And 1 mole contains $6.023$ x $10^{23}$ glucose molecules.

Therefore, $1.5$ moles contain $9.0345$ x $10^{23}$ molecules of glucose.

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