how many particles are there in 1.43g of a moleculat compound with a gram molecular mass of 233g
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Answer:
1.43g of compound (GMM=233g) contains 3.69×10²¹ particles.
Explanation:
Given that,
mass of compound = 1.43g
molar mass of compound = 233g/mol.
the formula to find the number of moles is
number of moles = given mass / molar mass
⇒ = 1.43/233 = 6.14×10⁻³ mol.
1 mole of a substance contains 6.022×10²³ particles.
number of particles present in the compound is given by,
number of particle = number of moles× Avogadro's Number
⇒ =6.14×10⁻³ × 6.022×10²³ = 3.69×10²¹
Hence, the required answer is 3.69×10²¹
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