Question

How many percent of the Earth's surface would be covered by the surface of the moon, if the radius of the earth is 6,378 km and the radius of the moon is 1,741 km?

Answer 1

Answer:

The formula for a surface area is 4∗pi∗r2.4∗pi∗r2.

Using this, we can calculate the SA of the Earth and the Moon.

SA of Earth = 511,185,933 miles squared.

SA of Moon = 38,089,687 miles squared.

SAEarth/SAMoon=0.075=7.5SAEarth/SAMoon=0.075=7.5%

trying to learn how to use equations but its failing on me :

Answer 2

Given,

The radius of Earth = 6, 378 km

The radius of the moon = 1,741 km

To find,

What percentage of the Earth's surface would be covered by the surface of the moon.

Solution,

We Know That area of circle = (3.14) $r^2$

Area of Earth = π $(6,378)^2$

                      ⇒ π 4,06,78,884

Area of Moon = π $(1,741)^2$

                       ⇒ π 30,31,081

∵ Percentage of Surface Area that will be covered = $\frac{30,31,081}{4,06,78,884}$ × 100

⇒ 7.451239321118052

≈ 7.5%

∴ The percentage of Earth's Surface Area that will be covered by the moon is 7.5%

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