How many permutation can be made out of the letters of word TRIANGLE if T and E occupy the end places.
Answers
Answered by
34
The given word is TRIANGLE.
There are 8 letters in it.
It is said that T and E occupy the end places. So the word can become:
T _ _ _ _ _ _ E or
E _ _ _ _ _ _ T
Thus there are 2 possibilities.
Now, we have to arrange the remaining 6 letters in the remaining 6 places.
So, number of arrangements =
6P6
= 6!
= 720
Thus, total number of permutations is
= 2×720
= 1440
Thus, there are 1440 possible words.
There are 8 letters in it.
It is said that T and E occupy the end places. So the word can become:
T _ _ _ _ _ _ E or
E _ _ _ _ _ _ T
Thus there are 2 possibilities.
Now, we have to arrange the remaining 6 letters in the remaining 6 places.
So, number of arrangements =
6P6
= 6!
= 720
Thus, total number of permutations is
= 2×720
= 1440
Thus, there are 1440 possible words.
nallanagulasaip:
ur answering way is ossum
Answered by
2
Step-by-step explanation:
The given word is TRIANGLE.
There are 8 letters in it.
It is said that T and E occupy the end places. So the word can become:
T _ _ _ _ _ _ E or
E _ _ _ _ _ _ T
Thus there are 2 possibilities.
Now, we have to arrange the remaining 6 letters in the remaining 6 places.
So, number of arrangements =
6P6
= 6!
= 720
Thus, total number of permutations is
= 2×720
= 1440
Thus, there are 1440 possible words.
Similar questions