Question

How many permutations can be made by

using all the letters of the word

'MATHEMAGICA' ?

(1) (11)! (2) (420)(8!)

(3) 11!

2!2! (4) (660)7!​

Answer 1

Answer: total no of letters = 11 . And a repeats 3 times and m repeats 2 times then total no permutations = 11!/2!×3!= 660×7!

So option 4) is correct . If my answer help you mark as brainlist .

Answer 2

Given

• MATHEMAGICA

To find

• permutations possible with the word

Solution

we are provided with a word and are asked to find the permutations possible with the word. it must be noted that the letters of the word repeats and must be taken care of during the usage of the formula associated with permutation.

total number of letters in the word = 11

number of times the letter M repeats = 2

number of times the letter A repeats = 3

apart from these two letters no other letters repeats as the possible permutations would be,

n!/(a! × b! ...)

or, permutation = 11!/(2! × 3!)

or, permutation = 660 × 7!

therefore the option d is correct