Math, asked by MaheshkumarSahu, 1 year ago

how many persons can be accommodated in the Hall Of length 16 breadth 12.5 M and height 4.5 m and assuming that 3.6 M cube of air is required for each person


KHEMANI: 900/3.6 =250 people
MaheshkumarSahu: divide it you will get the answser

Answers

Answered by MegaRayquaza16
8
Number of people who can survive(lol) in the room is= \frac{Volume of air in the room}{volume required per person}

= \frac{LBH}{3.6}
= \frac{900}{3.6}
=250 people
Answered by nilamkumari91229
3

Answer:

your answer is given above

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