how many photons of light having a wavelength 4000A are necessary to provide one joule of energy
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Answered by
17
n=wavelength×E/hc
n=4000×10^-10/(6.63×10^-34×3×10^8)
n=202.02×10^16.photons
or
n=2.02×10^18 no.of photons.
n=4000×10^-10/(6.63×10^-34×3×10^8)
n=202.02×10^16.photons
or
n=2.02×10^18 no.of photons.
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24
Hope it may helps you....
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