how many photons of wavelength lamda is equals to 600 nm must strikes a totally reflecting screen per second at normal incidence. so as to exert a force of 1 N?
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Explanation:
I think its best to use the Impulse-Momentum theorem.
Net External force= dP/dt. or (Integration) Fdt = (Integration) dP
Use de Broglie concept which says
h(plank’s constant)/P(momentum)=Wavelength
In all,
(10N)*(1s)= n(no of photons)*(delta P(net))=(n)*2(h/wavelength)
The answer should probably be (5)*10^27.
h=[6.63*(10^(-34)] And of course don’t forget the collisions are elastic in nature
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