Question

How many pi and sigma bonds are present in the resonating form of naphthalene molecule?

Answer 1

There are 5 double bonds (C=C), 6 C-C single bonds and 8 C-H single bonds in this molecule.



The C-H bonds are indicated by numbers (in red colour), while the C-C single bonds are indicated by alphabets. The 5 C=C bonds in the molecule. As each double bond in a molecule consists of a sigma bond and a pie bond, therefore in naphthalene there are total 19 sigma bonds (6 C-C single bonds, 8 C-H single bonds and 5 from C=C bonds) and 5 pie bonds.

Answer 2

Explanation:

Following is the structure of naphthalene

 

 

As evident from the above structure, there are 5 double bonds (C=C), 6 C-C single bonds and 8 C-H single bonds in this molecule. This can be further explained from the following structure

 

The C-H bonds are indicated by numbers (in red colour), while the C-C single bonds are indicated by alphabets. The above structure also shows the 5 C=C bonds in the molecule. As each double bond in a molecule consists of a sigma bond and a pie bond, therefore in naphthalene there are total 19 sigma bonds (6 C-C single bonds, 8 C-H single bonds and 5 from C=C bonds) and 5 pie bonds.