Math, asked by Zoe67, 6 months ago

How many pieces each of length 4 4/1m can be cut out of a rope of length of 68m​

Answers

Answered by bulemanisha5
1

Answer:

8 pieces can be cut.

Step-by-step explanation:

Length of rope = 30m

Length of piece cut =

\begin{gathered}3 \frac{3}{4} = \frac{(4 \times 3) + 3}{4} = \frac{15}{4} m \\\end{gathered}

3

4

3

=

4

(4×3)+3

=

4

15

m

\begin{gathered}number \: of \: pieces \: that \: can \: be \: cut \: = \frac{length \: of \: rope}{length \: of \: piece \: cut} \\ = \frac{30}{ \frac{15}{4} } \\ = 30 \times \frac{1}{ \frac{15}{4}} \\ = 30 \times \frac{4}{15} \\ = 15 \times 2 \times \frac{4}{15} \\ = 4 \times 2 \\ = 8\end{gathered}

numberofpiecesthatcanbecut=

lengthofpiececut

lengthofrope

=

4

15

30

=30×

4

15

1

=30×

15

4

=15×2×

15

4

=4×2

=8

Answered by simone7773
0

Answer:

1. if u mean 4 m then 17 pcs

2. if u mean 4 4/1 then 8

Step-by-step explanation:

1.

length of;

rope = 68 m

each piece = 4 m

total pcs = 68 ÷ 4

= 17

a total of 17 pieces can be cut out of the rope

.

.

2.

length of;

rope = 68 m

each piece = 4 4/1m

= 4 + 4m

= 8 m

total pcs = 68 ÷ 8

= 8 (r - 4 m)

a total of 8 pieces (with a remainder of 4 m rope) can be cut out of the rope

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