Question

how many pieces of stone slabs each 26 cm long 10 cm broad will be required to lay a part 26 metre and length and 15 metre wide​

Answer 1

Answer:

15,000

Step-by-step explanation:

Dimensions of slabs

l(slab)=26cm

b(slab)=10cm

Dimensions of part

l(part)=26m=2600cm

b(part)=15m=1500cm

Area of slab=l(slab)×b(slab)

=26cm×10cm

=260cm²

Area of part=l(part)×b(part)

=2600cm×1500cm

3900000cm²

No. of bricks required=

$\frac{area \: of \: part}{area \: of \: slab}$

$\frac{ {3900000cm}^{2} }{ {260cm}^{2} }$

$\frac{30000}{2}$

=15000

So, 15,000 slabs are required to lay the part.