How many polynomials are there having 3 and -5 as zeroes?
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Answer:
one / infinite
Step-by-step explanation:
How many polynomials are there having 3 and -5 as zeroes?
f(x) = (x-3)(x - (-5)) Having 3 & - 5 as zeroes
=> f(x) = (x-3)(x + 5)
=> f(x) = x² + 2x - 15
Polynomial = f(x) = x² + 2x - 15
Multiplying by k
kx² + 2kx - 15k
Polynomial given above have 3 & -5 as zeroes
Putting different value of k we can get infinite Polynomial which on dividing by k will result into a unique polynomial x² + 2x - 15
If there can be additional zeroes of polynomial other than 3 & - 5
then again infinite polynomial
(x - α)(x-β).(x² + 2x - 15) and so on
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