How many positive integer x are there such that 3x has 3 digits and 4x has 4 digits?
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100x+10x+1x=3x
111x=3x
111x-3x=0
x=1/108
therefore there are 108 possible positive integers which can be expressed as in the question.
111x=3x
111x-3x=0
x=1/108
therefore there are 108 possible positive integers which can be expressed as in the question.
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