how many positive integer X are there such that 4x has four digit and 5x has five digit
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X also has only one one digit
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Number of positive integers ‘x’ where 3x has 3 digits
The smallest 3-digit multiple of 3 = 102 (3x). So ‘x’ is 34.
The largest 3-digit multiple of 3 = 999 (3x). So ‘x’ is 333.
So there are 300 (333–34+1) positive integers for which ‘3x’ has 3 digits
They are from 34 to 333.
Number of positive integers ‘x’ where 4x has 4 digits
The smallest 4-digit multiple of 4 = 1000 (4x). So ‘x’ is 250.
The largest 4-digit multiple of 4 = 9996 (4x). So ‘x’ is 2499.
So there are 2250 (2499–250+1) positive integers for which ‘4x’ has 4 digits
They are from 250 to 2499.
So the number of integers satisfying both the conditions would be
333–250+1 = 84.
The smallest 3-digit multiple of 3 = 102 (3x). So ‘x’ is 34.
The largest 3-digit multiple of 3 = 999 (3x). So ‘x’ is 333.
So there are 300 (333–34+1) positive integers for which ‘3x’ has 3 digits
They are from 34 to 333.
Number of positive integers ‘x’ where 4x has 4 digits
The smallest 4-digit multiple of 4 = 1000 (4x). So ‘x’ is 250.
The largest 4-digit multiple of 4 = 9996 (4x). So ‘x’ is 2499.
So there are 2250 (2499–250+1) positive integers for which ‘4x’ has 4 digits
They are from 250 to 2499.
So the number of integers satisfying both the conditions would be
333–250+1 = 84.
khushi5280aarvi:
options are 600,601,500,501
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