Question

How many positive integers greater than 5,000,000 can be formed using the digits 2, 3, 3, 5, 5, 6, 8?

Answer 1

Answer:

48

Step-by-step explanation:

Since any number greater than 50,000 contains 5 digits, we have to take all the 5 digits out of which the digit 6 is repeated twice.

So number of permutations is

2!

5!

=60

But out of these arrangements we have to reject those which begin with 3 as in that case, the numbers will be less than 50000.

We find all such numbers by fixing 3 at extreme left. So remaining 4 digits can be filled in

2!

4!

=12

Required number of number is 60−12=48

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