how many positive integers less than 100 can be written as the sum of 11 consecutive integers
Answers
Given : positive integers less than 100 can be written as the sum of 11 consecutive integers
To Find : How many
Solution:
from - 5 to + 5 , 11 consecutive integers sum would be zero
looking for positive integers
Hence
1st case -4 to + 6 sum = 11
2nd case -3 to 7 sum = 22
3rd case - 2 to 8 sum = 33
4th case -1 to 9 sum = 44
5th case 0 to 10 sum = 55
6th case 1 to 11 sum = 66
7th case 2 to 12 sum = 77
8th case 3 to 13 sum = 88
9th case 4 to 14 Sum = 99
9 positive integers less than 100 can be written as the sum of 11 consecutive integers
if consecutive integers are also need to be positive
Then 4 case
1 to 11 => Sum = 66
2 to 12 => Sum = 77
3 to 13 => sum = 88
4 to 14 => Sum = 99
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