Question

How many positive integers less than 4300 of digits 0-4.

a.560 b)565 c)575 d)625?

Answer 1

Answer:

574

Step-by-step explanation:

How many positive integers less than 4300 of digits 0-4.

a.560 b)565 c)575 d)625?

1 digit number  = 4   ( 1 to 4)

2 Digit number =  4 * 5  =  20    ( 1st digit can be 1 to 4  & 2nd digit can be 0 to 4)

3 digit number = 4 * 5 * 5 = 100  ( 1st digit can be 1 to 4  & 2nd & 3rd digit digit can be 0 to 4)

4 digit number till 3999

4 digit number = 3 *  5 * 5 * 5 = 375  (  1st digit can be 1 to 3  & 2nd , 3rd & 4th digit digit can be 0 to 4)

4 digit number ≥ 4000 & ≤ 4300

= 1 * 3 * 5 * 5 = 75     (1st digit 4 , 2nd digit 0 , 1 & 2 & 3rd & 4th digit digit can be 0 to 4)

Total numbers = 4 + 20 + 100 + 375 + 75 = 574

if Question is how many positive integers not more than 4300 of digits 0, 1, 2, 3, 4 then 4300 will also be included

then 574 + 1 = 575