Question

How many positive, integers N give a remainder 8 when 2008 is divided by N

Answer 1

Answer:

20 => ANSWER

MARK AS "BRAINIEST" ANSWER.

Step-by-step explanation:

Answer 2

Step-by-step explanation:

if 2008 is divided by N then by division algorithm

2008=N*q(x)+8

2000=N*q(x)

this means N divides 2000

by prime factorisation 2000=2^4×5^3

so no of divisors are

(4+1)*(3+1)=20

so no of integers are 20