Question

how many positive or negative charges are present in 300 grams of water ​

Answer 1

Answer:

Total no. of electrons or protons present in a cup of water,n’=n×10=8.36×10^25

Explanation:

Answer 2

Answer:

Hi ..

Assume that one cup holds 250 ml of water.

250 ml = 250 gram of water since its density is 1 in cgs.

number of moles of water in 250 gram = 250 / molar weight of water

n = 250/18 = 13.88 moles

1 mol has 6.022 x 1023 number of water molecules

So 250 g water will have 13.88 x 6.022 x 1023 number of H2O molecules

= 8.36 x 1024 number of molecules

One molecule of water has 2 hydrogen atoms (2 protons) and one oxygen atom (8 protons).

Total protons = 10 = total electrons (since it is neutral)

So 250 g water will have 10 x 8.36 x 1024 = 8.36 x 1025 protons.

charge of proton = 1.6 x 10-19 C

So total positive charge of 250 g water = 1.6 x 10-19 x 8.36 x 1025 = 13.37 x 106 C

which is equal to 13.3 MC (mega coulomb)

So one cup of water has 13.3 mega coulomb positive and negative charge, so that the overall charge is zero...

Hope this helps u!!