Question

how many possibilities are there when One number is selected from 15 to 30​

Answer 1

Answer:

1/16 is the answer ...........

Answer 2

Answer:

Problem Based on probability concept

Step-by-step explanation:

So , In order to find the total outcomes we have to form the A.P. 15 , 16 , 17 , 18 , ............................ , 30.

This A.P. is with common difference D with 16 - 15 = 1 and a = 15 , n = no.of terms = ? , last term = 30.

So , by the formula :-

$a_{n} \: = a \: + \: (n - 1)(d)$

So by substituting the respective values we get ,

30 = 15 + (n-1)(1)

30 = 15 + n - 1

30 = 15 - 1 + n

30 = 14 + n

30 - 14 = n [BY APPLICATION OF LINEAR EQUATION]

n = 16.

There are total 16 outcomes . So , when one number is selected at random from this stack of numbers . There are total 16 cases :-

All 16 cases have the possibility of 1 / 16 .

CASE 1 :-

Because when we chose 15 (say).

The favourable outcomes of this event is 1.

Total outcomes = 16

P(15) = Favourable outcomes / Total outcomes

P (15) = 1 / 16.

CASE 2 :-

CASE 3 :-

CASE 4 :-

CASE 5 :-

CASE 6 :-

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CASE 16 :-

Same method in all other 15 cases . Just put the value of that number in P() that you want to take from the stack of numbers 16 to 30.

So , this is considered to be elementary event .

Answer :- SO THE ANSWER OF PROBABILITY IS 1 / 16 IN ALL THE CASES .

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