Question

how many possible combinations can be made with this number 1234567890​

Answer 1

Step-by-step explanation:

$\huge\red{\mathfrak{ Answer }}$

hey mate

You can make infinite combination of numbers using the given digits of number as it contains all 10 digits which is required to form any number

hope it helps ✌

Answer 2

Answer:

The answer is known as a factorial, which for the number 1234567890 of 10 total digists = 10! = 1 x 2 x 3 x 4 x 5 x 6 x 7 x 8 x 9 x 10 = 3,628,800 - a little under 3.3 million possible combinations

Step-by-step explanation:

Step 1: The sequence of the results is irrelevant when calculating the overall outcomes of an event using combinations. We will use the formula nCr = n! / r! * (n - r)! to compute combinations, where n denotes the total number of items and r denotes the number of things being picked at a time.

Step 2:1-digit combos: 1, 2, 3, 4, 5, 6, 7, 8, 9, 0 (10 total combos)

2-digit combos: 12, 23, 34, 45, 56, 67, 78, 89, 90 (9)

3-digit combos: 123, 234, 345, 456, 567, 678, 789, 890 (8)

Do you notice the pattern? Each time the number of digits increases, the number of total combos decreases, so your answer will be the same as 1 + 2 + 3 + 4 + … + 10. Hence, we get 55.

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