Math, asked by akshitsharma6423, 11 months ago

How many pounds of chocolate worth $1.5 a pound must be mixed with 10 pounds of chocolate worth 60 cents a pound to produce a mixture worth $1 a pound?

Answers

Answered by sushant2586
0

Answer:

8 pounds of chocolate worth $1.5 must be mixed.

Step-by-step explanation:

Let the chocolate worth $1.5 be = P

10 pounds of chocolate is worth 60 cents a pound, i.e. $0.6

When mixed, total weight T = P + 10

Total mixture is worth $ 1.

Therefore we can write the costing as

1.5× P + 10×0.6 = 1 × (P+10)

Solving the equation for P,

1.5P + 6 = P + 10

1.5P - P = 10 - 6

0.5P = 4

P = 8

∴ 8 pounds of chocolate worth $1.5 must be mixed.

Answered by amitnrw
0

Answer:

8 pounds

Step-by-step explanation:

How many pounds of chocolate worth $1.5 a pound must be mixed with 10 pounds of chocolate worth 60 cents a pound to produce a mixture worth $1 a pound?

Let say x pound of chocolate worth $1.5 / pound is mixed with

10 pounds of chocolate worth 60 cents /pound

60cents = 60/100 $ = 0.6 $

Total chocolate = x + 10 pound

Total cost = x * 1.5 + 10*.6 = 6 + 1.5x $

Cost per pound = ( 6 + 1.5x)/(x+10)  $

Cost Per pond =   $ 1

( 6 + 1.5x)/(x+10)  = 1

=> 6 + 1.5x = x +10

=> 0.5x = 4

=> x = 8

8 pound of chocolate worth $1.5 a pound must be mixed

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