Question

How many proteins of average size could be encoded in a virus with a dna genome having 12,000 bp, assuming no overlap of genes?

Answer 1

Answer:

2,134 proteins of average size could be encoded in a virus with a dna genome having 12,000 BP, assuming no overlap of genes.

Hope it Helps !!!!

Answer 2

Solution:

10 proteins of the average size of 400bs will be synthesized.

Explanation:

• If the virus genome is of size 12000 bp and there is no overlap of genes.
• The average size of protein in a virus can be 400 amino acids.
• Each codon has 3 base pairs and each codon will synthesis for 1 amino acid that has 3 nucleotides or base pairs.
• For average-sized protein of 400 amino acids will require 400 codons means 1200 base pairs (3×400).
• Hence, the total number of proteins synthesized is the total size of the genome in base pair ÷ size of protein in base pair
• =12000÷1200
• =10 proteins

A 400 aa sized protein will need 400 codons = 3 x 400 = 1200 bp

Hence the total number of proteins that can be made is,

Total size of genome in bp/Size of 1 protein in bp = 12000/1200 = 10

The answer is 10 proteins of average length 400 aa.