how many proton are present in 5.6litre of oxygen at NTP
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Therefore, 5.6 L is occupied by 0.25 moles of a gas, which will therefore contain 0.25 x 6.023 x 10^23 particles.1.50575 * 10^23 molecules of Oxygen gas in 5.6 L. One molecule contains 2 atoms of oxygen, so the number of atoms is double the number of molecules. 3.0115 * 10^23 atoms of oxygen in 5.6 L oxygen gas.
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