Question

how many proton neutron and electron present in 0.18 gram in15p ​

Answer 1

Explanation:

A=30 and Z=15

no.of protons in one atom of p=no.of electrons in one atom of p=15

no.of neutrons in one atom of p=(A-Z)

30_15=15

0.18grm of p =0.18/30=0.006mol

no.of atoms in 0.006mol= 0.006×6.02×10^23

no.of protons in 0.006mol of p=15×0.006×6.02×10^23=5.148×10^22

so, no.of electrons =5.418×10^22

no.of neutrons =5.418×10^22

Answer 2

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