Chemistry, asked by jaroliraj940, 7 months ago

How many protons are present in
4 g NaOH?
(a) 6.022 x 1023
(b) 12.044 x 1023
(c) 12.044 x 1024
(d) 6.022 x 10​

Answers

Answered by harshit8335
0

Answer:

6.023 x 10^23

Explanation:

hope it's help u

Answered by daivikdalwadi10
0

Answer:

Molar mass NaOH = 40 g/mol

  • 4 g NaOH = 0.1 mol

  • 1 mol atoms = 6.022*10^23 atoms

  • You have 0.1 mol Na atoms . That is 6.022*10^22 Na atoms, Atomic number Na = 11

  • Each atom has 11 protons . Total protons = 6.022*10^22 * 11 = 6.62*10^23 protons

  • You have 0.1 mol O atoms . That is 6.022*10^22 O atoms, Atomic number O= 8

  • Each atom has 8 protons . Total protons = 6.022*10^22 * 8 = 4.82 *10^23 protons

  • You have 0.1 mol H atoms . That is 6.022*10^22 H atoms, Atomic number H = 1

  • Each atom has 1 protons . Total protons = 6.022*10^22 * 1 = 6.02*10^22 protons

  • Total number of protons = 6.62*10^23 +4.82 *10^23 +6.02*10^22 protons

  • Total protons = 1.20*10^24 protons

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