Question

How many protons, electrons and neutrons are present in 2.4 g of a S atom?​

Answer 1

as in sulphur...number of p,n,e are=16

thus,for 2.4g moles of sulphur(n)=given mass/molar mass=2.4÷32=3/40

hence,we know that:;

no of moles=no of e,p or n/avagadro no(NA)

:no of p,n and e=moles×NA

=3/40×NA×16(as stated earlier☝️)

=1.2×NA(ans)

hence,,no of e ,p,n➡️1.2NA