How many protons, electrons and neutrons are present in 2.4 g of a S atom?
Answers
Answered by
2
as in sulphur...number of p,n,e are=16
thus,for 2.4g moles of sulphur(n)=given mass/molar mass=2.4÷32=3/40
hence,we know that:;
no of moles=no of e,p or n/avagadro no(NA)
:no of p,n and e=moles×NA
=3/40×NA×16(as stated earlier☝️)
=1.2×NA(ans)
hence,,no of e ,p,n➡️1.2NA
Similar questions