How many quarts of water must be added to 4 quarts of an 80% mixture to obtain a 50% mixture?
Answers
Answered by
3
Volume of water in the 4 quarts = 20% x 4 = 0.8 quarts
Let the volume of water to be added = x quarts
Total volume = (x + 4) quarts
This volume contains 50% water
so;
(0.8 + x)/(x + 4) x 100 = 50
(0.8 + x)/(x + 4) = 0.5
0.8 + x = 0.5x + 2
x - 0.5x = 2 - 0.8
0.5x = 1.2
x = 2.4
2.4 quarts of water needs to be added
Let the volume of water to be added = x quarts
Total volume = (x + 4) quarts
This volume contains 50% water
so;
(0.8 + x)/(x + 4) x 100 = 50
(0.8 + x)/(x + 4) = 0.5
0.8 + x = 0.5x + 2
x - 0.5x = 2 - 0.8
0.5x = 1.2
x = 2.4
2.4 quarts of water needs to be added
Answered by
2
Answer:
Step-by-step explanation:
Volume of water in the 4 quarts = 20% x 4 = 0.8 quarts
Let the volume of water to be added = x quarts
Total volume = (x + 4) quarts
This volume contains 50% water
so;
(0.8 + x)/(x + 4) x 100 = 50
(0.8 + x)/(x + 4) = 0.5
0.8 + x = 0.5x + 2
x - 0.5x = 2 - 0.8
0.5x = 1.2
x = 2.4
2.4 quarts of water needs to be added
Similar questions