Question

how many radial nodes for 2s 4p 5d and 4f orbital exhibit? how many angular nodes? ​

Answer 1

Answer:

2 angular nodes

Explanation:

Number of radial nodes = n – l – 1. So, 4p orbital has 2 radial nodes and 1 angular node. Number of radial nodes = n – l – 1 = 5 – 2 – 1 = 2 radial nodes. ∴ 5d orbital have 2 radial nodes and 2 angular nodes.

Answer 2

Given: The given orbitals are 2s, 4p, 5d and 4f.

To find: We have to find the number of angular and radial nodes.

Solution:

We know that,

The number of radical nodes=n-l-1 and the number of angular nodes is equal to l.

For 2s orbital l=0 so, the number of angular nodes are 0.

The number of radical nodes=2-0-1

2-0-1=1.

For 4p orbital l=1 so, the number of angular nodes is 1.

The number of radical nodes=4-1-1

=2.

For 5d orbital l=2 so, the number of angular nodes is 2.

The number of radical nodes=5-2-1

=2.

For 4f orbital l=3 so, the number of angular nodes are 3.

The number of radical nodes=4-3-1

=0.

The number of angular nodes for 2s 4p 5d and 4f orbitals is 0,1,2,3 and the number of radical nodes is 1,2,2,0.