Question

How many radial nodes for 2s, 4p, 5d and 4f orbitals exhibit? How many angular nodes?

Answer 1

we know, angular nodes = l and radial nodes = n - l - 1
where n is principle quantum number and l is azimuthal quantum number.

for 2s : n = 2 and l = 0
so, angular nodes = 0
radial nodes = 2 - 0 - 1 = 1

for 4p :- n = 4 and l = 1
Angular nodes = l = 1
radial nodes = 4 - 1 - 1 = 2

for 5d : n = 5 and l = 1
angular nodes = 1
radial nodes = 5 - 1 - 1 = 3

for 4f : n = 4 and l = 3
angular nodes = 3
radial nodes = 4 - 3 - 1 = 0

Answer 2

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