how many real roots does the equation ( x^2 + 2 )^2 - x^2 = 0 have ? ( fast please )
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Answer:
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Step-by-step explanation:
( x² + 2)² - x² = 0
=> (x² + x+2) (x²-x+2) = 0
D= b² - 4ac = 1² - 4×2 = 1-8 < 0
Hence, this equation has no real roots.
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