Math, asked by noobnrg, 6 months ago

How many real roots the equation (x+1) (x+2) (x+3) (x+4)=24 has​

Answers

Answered by Anonymous
1

Step-by-step explanation:

ANSWER

(x−1)

2

+(x−2)

2

+.............+(x−n)

2

=0

clearly this is a quadratic equation equation equation since all the terms are quadratic.

Now, we know square of any term is always non-negative .

Therefore,

This equation will never cross x-axis that is it will always be greater than zero.

The parabola graphically will never cross x-axis and hence there will be no real solution.

Hence, the answer zero.

Answered by THEGOODBOY90
0

Answer:

hey watch the above pic for ur answer of the question.

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